Question

Please Geniuses, look at the picture and answer me, RESCUE ME.


Q1. if A:B= 6:5 and B:C= 18:6, then find A:C in its simplest term

A. 18:15
B. 15:18
C. 6:5
D. 5:6
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Answer 1

Answer:

1. $\{ \bold{ \sf{Expenditure \: on \: food = \:1200 dollars\: }}$

2. $\sf{a \: : \: c \: = 18 \: : \: 5}$

Step-by-step explanation:

1. $\sf{here \: total \: expenditure = 3000 \: dollars}$

$\sf{expenditure \: on \: food \: = \: \frac{3000}{360} \times 144}$

$\sf{expenditure \: on \: food{ = 1200 \: dollars}}$

Note : Whole circle represents the total expenditure.

i.e 360° represents $ 3000

1° represents $ $\sf{ \frac{3000}{360} }$

144 ° represents $ $\sf{ \frac{3000}{360} \times 144}$

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2. $\sf{here \: a:b \: = 6:5 \: = \: \frac{6}{5} }$

$\sf{b : \: c \ \: = 18 \: : \: 6} \: = \: \frac{18}{6}$

$\sf{now \: a:b \times b:c = \frac{a}{b} \times \frac{b}{c} = \frac{a}{c} }$

⇒$\sf{a:c = \frac{6}{5} \times \frac{18}{6} }$

⇒$\sf{a:c = \frac{18}{5} }$

⇒$\sf{a:c = 18:5}$

Hope I helped!

Best regards!!