Question

In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube length is 25 cm. What is the magnitude of the overall magnification of the microscope?

Answer 1

Answer:

m = 312.5

Explanation:

Given that,

The focal length of the objecive lens, $f_o=1\ cm$

The focal length of eye piece, $f_e=2\ cm$

length of the tube, L = 25 cm

We need to find the magnitude of the overall magnification of the microscope. It is given by the formula as follows :

$m=\dfrac{L}{f_o}\times \dfrac{D}{f_e}$

D = 25 cm

So,

$m=\dfrac{25}{1}\times \dfrac{25}{2}\\\\m=312.5$

So, the overall magnification of the microscope is 312.5.