Answer:
- 6 = (2,2)
- 8 = (0, -6)
- 10 =(13,-6)
Step-by-step explanation:
[tex]Midpoint = (\frac{x_2+x_1}{2} , \frac{y_2+y_1}{2} )\\[/tex]
6.
[tex](5.8) =(x_1,y_1)\\(-1,-4) =(x_2,y_2)\\\\Midpoint =\left(\frac{-1+5}{2},\:\frac{-4+8}{2}\right)\\\\Midpoint =( \frac{4}{2} , \frac{4}{2} )\\\\Midpoint = ( 2 , 2)[/tex]
8.
[tex](-3 ,-7) =(x_1 ,y_1)\\(3,-5)=(x_2,y_2)\\\\\left(\frac{3-3}{2},\:\frac{-5-7}{2}\right)\\ \\Midpoint = (\frac{0}{2} , \frac{-12}{2} )\\\\Midpoint = ( 0, -6)[/tex]
10.
[tex]L(-9 ,4) =(x_1 ,y_1)\\K(2 , -1 ) = (x ,y )\\M(x_2 ,y_2 )=?\\ \\x = \frac{x_2+x_1}{2}\\ 2 = \frac{x_2 +(-9)}{2}\\ 2 = \frac{x_2-9}{2}\\ Cross\:Multiply\\\\4 =x_2-9\\4+9=x_2\\13 =x_2\\\\y = \frac{y_2+y_1}{2}\\ -1 = \frac{y_2 +4}{2} \\-1 \times 2= y_2+4\\-2 =y_2+4\\-2-4 =y_2\\-6 =y_2\\\\(x_2 ,y_2) = (13 , -6)\\[/tex]
