Question

A solid oblique pyramid has a regular hexagonal base with an area of 54StartRoot 3 EndRoot cm2 and an edge length of 6 cm. Angle BAC measures 60°. A solid oblique pyramid has a regular hexagonal base with an area of 54 StartRoot 3 EndRoot centimeters squared and an edge length of 6 centimeters. Point B is the apex and point A is the center of the hexagon. Point C is a corner of the hexagon. Triangle A B C is formed. Angle A is 60 degrees and angle C is 90 degrees. What is the volume of the pyramid? 72StartRoot 3 EndRoot cm3 108StartRoot 3 EndRoot cm3 324 cm3 486 cm3

Answer 1

Answer: C. 324 cm∧3

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Answer 2

Based on the calculations, the volume of this pyramid is equal to: D. 324 cm³.

Given the following data:

• Base area = 54√3 cm².

• Edge length = 6 centimeters.

• Angle BAC = 60°.

How to calculate the volume of a pyramid?

Mathematically, the volume of a pyramid can be calculated by using this formula:

Volume = 1/3 × base area × height

Next, we would find the height of this pyramid from the right-angled triangle ABC by applying Tan trigonometry formula:

Tanθ = Opp/Adj = BC/AC

Tan60 = height/6

√3 = height/6

Height = 6√3 cm.

Now, we can calculate the volume of this pyramid:

Volume = 1/3 × base area × height

Volume = 1/3 × 54√3 × 6√3

Volume = 1/3 × 972

Volume = 324 cm³.

Read more on pyramid here: brainly.com/question/16315790

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