Question

I need help with these 2 problems

Answer 1

Answer:

Step-by-step explanation:

hello, you know that

$\sqrt[5]{x^5}=x$

so, I can write

$\sqrt[5]{2^5}=\sqrt[5]{32}=2\\\\\sqrt[5]{3^5}=\sqrt[5]{243}=3\\\\\sqrt[5]{4^5}=\sqrt[5]{1024}=4\\\\\sqrt[5]{5^5}=\sqrt[5]{3125}=5$

So, the winners are 32, 243, 1024, 3125 !!

You know that $i^2=-1$, right?

$\sqrt{-9}=\sqrt{(3i)^2}=3i$

So, the answer is 3i

Thank you