Question

When x=3 ,y=16 and when x=6 y=8. Which inverse variation equation can be used to model this function?

Answer 1

Answer:

$y=\frac{48}{x}$

Step-by-step explanation:

When x = 3, y = 16

When x = 6, y = 8

We need to model the inverse variation.

Inverse Variation : When one value increase another value decrease. But product of both always constant.  

$xy=k$

when x=3, y=16

k=48

When x=6, y=8

k=48

Model of the inverse variation:

$y=\frac{48}{x}$

Hence, The model of inverse variation is

$y=\frac{48}{x}$

Answer 2

Answer:

The inverse variation equation can be used to model this function is:

$y=\frac{48}{x}$

Step-by-step explanation:

An inverse relationship between two variables implies that if the value of one variable increases the value of the other variable will decreases and vice-versa.

The inverse function describing the relationship between x and y is as follows:

$y=\frac{a}{x}$

Here, a is a constant.

It is provided that when the value of x is 3 the value of y is 16.

Compute the value of a as follows:

$y=\frac{a}{x}$

$16=\frac{a}{3}$

$a=48$

It is also provided that when the value of x is 6 the value of y is 8.

Compute the value of a as follows:

$y=\frac{a}{x}$

$8=\frac{a}{6}$

$a=48$

The value of a is 48.

Then the inverse variation equation can be used to model this function is:

$y=\frac{48}{x}$