this is my third time posting this bc i kept getting the wrong answer please help me

Answer:
B
Step-by-step explanation:
So we have:
[tex]\frac{x^{\frac{2}{3}}}{y^{\frac{-3}{4}}}[/tex]
First, we recall that we can switch an exponent from the denominator to the numerator if we multiply the exponent by -1 and vice versa. Therefore:
[tex]=x^{\frac{2}{3}}}\cdot {y^{\frac{3}{4}}[/tex]
Now, use the following property:
[tex]a^{x/n}=\sqrt[n]{a^x}[/tex]
Therefore:
[tex]x^{\frac{2}{3}}=\sqrt[3]{x^2}[/tex]
And:
[tex]y^{\frac{3}{4}}=\sqrt[4]{y^3}[/tex]
And so together:
[tex]=x^{\frac{2}{3}}}\cdot {y^{\frac{3}{4}}\\=\sqrt[3]{x^2}\cdot\sqrt[4]{y^3}[/tex]
Our answer is B :)