Answer:
Step-by-step explanation:
Hello, we assume that x is different from 0 and f different from 2b
[tex]b+\dfrac{3}{x}=\dfrac{f}{2}\\\\\text{Subtract b}\\\\+\dfrac{3}{x}=\dfrac{f}{2}-b\\\\\text{Mulitply by 2x}\\\\+\dfrac{3*2*x}{x}=6=\dfrac{2xf}{2}-2bx=(f-2b)x\\\\\text{Divide by f-2b}\\\\\Large \boxed{\sf \bf x=\dfrac{6}{f-2b}}[/tex]
Thanks