Question

What is the volume in milliliters, of a sample of helium that has a mass of 1.73 x 10^-3g given that the density is 0.178 47g/L

Answer 1

Given :

Mass of helium sample , $m=1.73\times 10^{-3}\ g$ .

Density of helium , $\rho=0.178\times 10^{-3} \ g/cm^3$ .

To Find :

The volume in millilitres .

Solution :

Density is given by , $\rho=\dfrac{m}{V}$

So , volume is , $V=\dfrac{m}{\rho}$

Putting given values in above equation we get :

$V=\dfrac{1.73\times 10^{-3}}{0.178\times 10^{-3}}\ ml\\\\V=9.72\ ml$

Therefore , volume of sample of helium is 9.72 ml .

Hence , this is the required solution .

Answer 2

The volume of sample in milliliters is 9.72 mL .

Given data:

The mass of sample is, $m=1.73 \times 10^{-3} \;\rm g$.

The density of the helium sample is, $\rho = 0.17847 \;\rm g/L =0.17847 \times 10^{-3} \;\rm g/cm^{3}$.

The given problem is based on the concept of density. The density of any substance is equal to the mass per unit volume of the substance. The expression is given as,

$\rho =\dfrac{m}{V}\\\\\\V =\dfrac{m}{\rho}\\\\\\V =\dfrac{1.73 \times 10^{-3}}{0.17847 \times 10^{-3}}\\\\V =9.72 \;\rm mL$

Thus, we can conclude that the volume of sample in milliliters is 9.72 mL .

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