Answer:
[tex] t = 4.942\times10^{3}[/tex]
Explanation:
we know that
[tex]t =-\frac{ln\frac{R}{R_0} }{\lambda}[/tex]
the symbols have their usual meaning
Also,
[tex]t=-T_{1/2}\frac{ln\frac{R}{R_0} }{ln2}[/tex]
now plugging the values we get
[tex]t=-5730\frac{ln(0.55) }{ln(2)}[/tex]
[tex] t = 4.942\times10^{3}[/tex] years