Answer: [tex]\dfrac{d-0.5at^2}{t}=v_i[/tex]
Explanation:
[tex]d=v_it+0.5at^2\\\\\\\text{Subtract}\ 0.5at^2\ \text {from both sides:}\\d-0.5at^2=v_it\\\\\\\text{Divide both sides by t:}\\\dfrac{d-0.5at^2}{t}=v_i[/tex]
