Question

ind the value of the 60th term of the following sequence: 33, 28, 23, 18...

Answer 1

Answer:

-262

Step-by-step explanation:

Given sequence is: 33, 28, 23, 18...

First term a = 33

Common Difference d = 28 - 33 = - 5

To find: $t_{60}$

By nth term of an AP.

$t_n = a + (n - 1)d \\ t_{60} = 33 + (60- 1)( - 5) \\ t_{60} = 33 + 59( - 5) \\ t_{60} = 33 - 295\\ t_{60} = - 262$