Question

What is the power in a circuit that has a current of 12 A and a resistance of 100 Ω? (Note: 1 A2·Ω = 1 W) (1 point)

Answer 1

Answer:

$\boxed{\sf Power \ in \ the \ circuit = 14.4 \ kW}$

Given:

Current (I) = 12 A

Resistance (R) = 100 Ω

To Find:

Power (P) in the circuit

Explanation:

Formula:

$\boxed{ \bold{P = I^2 R}}$

Substituting value of I & R in the equation:

$\sf \implies P = {(12)}^{2} \times 100 \\ \\ \sf \implies P = 144 \times 100 \\ \\ \sf \implies P = 14400 \: A^2.\Omega \\ \\ \sf \implies P = 14400 \: W \\ \\ \sf \implies P = 14.4 \: kW$

$\therefore$

Power (P) in the circuit = 14.4 kW