Given :
Speed of bus for first 16 hours is , u = 15 km/h .
Distance he walked for next 0.4 hour is , v = 4.5 km/h .
To Find :
The average speed for the whole journey.
Solution :
Average speed is given by :
[tex]v_{avg}=\dfrac{u_1t_1+u_2t_2}{t_1+t_2}\\\\v_{avg}=\dfrac{15\times 16 + 4.5\times 0.4}{16+0.4}\\\\v_{avg}=14.74\ km/h[/tex]
Therefore , the average speed of the journey is 14.74 km/h .
Hence , this is the required solution .