meredith48034
meredith48034 meredith48034
  • 26-08-2020
  • Mathematics
contestada

please assist me with this problem: part 10​

please assist me with this problem part 10 class=

Respuesta :

jimrgrant1 jimrgrant1
  • 26-08-2020

Answer:

c

Step-by-step explanation:

Given

sinN = [tex]\frac{a}{b}[/tex] ( multiply both sides by b ) , then

a = bsinN → (a)

And

sinM = [tex]\frac{a}{y}[/tex] ( multiply both sides by y ), then

a = ysinM → (b)

Thus a is both (a) and (b)

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