5. Three times the width of a certain rectangle exceeds twice its length by two inches. Four times its length is twelve more
than its perimeter. Write a system of equations that could be used to solve this problem. (hint: P = 2L + 2W)
A. 3W = 2L + 2
2L = 2W + 12
B. 3W + 2 = 2L
4L = P - 12
C.3W = 2L + 2
4L + 12 =P
D. 2W + 2 = 2L
4L = 12 + P
E. 3W + 2 = 2L
4L = 12 + P
F. 2L - 2 = 3W
P = 4L - 12
plsss help
