Answer:
Step-by-step explanation:
[tex]J(-3,\,4)\ \ \implies\ y_J=4\\\\K(4,\,4)\ \ \implies\ y_K=4\\\\y_K=y_J\ \ \implies\ JK\parallel X{-}axis\ \implies\ H=|y_L-y_K|\quad\ \{for\ JK=base\}\\\\H=|-3-4|=|-7|=7\\\\\\ JK\parallel X{-}axis\ \implies\ B=JK=|x_J-x_K|=|-3-4|=7\\\\\\A=\frac12BH\\\\A=\frac12\cdot7\cdot7=24.5[/tex]