Question

A rectangular parking lot has a length that is 8 yards greater than the width. The area of the parking lot is 560 square yards. Find the length and the width.

Answer 1

Answer: length=28, width=20

Step-by-step explanation:

Let x=width, then length=x+8

x(x+8)=560

x²+8x=560

x²+8x-560=0

(x-20)(x+28)=0

x=20 or x=-28 (rej) since a width can't be negative

20+8=28

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