Question

let f(x)=x-3and h(x)=x2+6.what is (h⁰g)(1)​

Answer 1

Answer:

The answer is 10 .

Step-by-step explanation:

f(x) = x-3

h(x) = $x^{2} +6$

Now ,

  hog(1)

=h (1-3)

=h (-2)

= $(-2)^{2}$ +6

= 4+6

= 10