[tex]x + 2y = -1\\x=-2,0,3\\f(x)=y\\[/tex]
plug in each value of x in the function y:
[tex]-2+2y=-1\\2y=1\\y=\frac{1}{2}[/tex]
first point is [tex](-2, \frac{1}{2})[/tex]
so when x = -2, f(x) = 1/2
[tex]0+2y=-1\\2y=-1\\y=-\frac{1}{2}[/tex]
second point is [tex](0,-\frac{1}{2})[/tex]
so when x = 0, f(x) = -1/2
[tex]3+2y=-1\\2y=-4\\y=-2[/tex]
third point is [tex](3,-2)[/tex]
so when x = 3, f(x) = -2
