what is the length of AD, in centimeters?

Answer:
AD=2
Step-by-step explanation:
[tex]\frac{6}{12} =\frac{AB}{20} \\AB=\frac{6}{12} \times 20=10\\AD+DF+FB=10\\AD+6+FB=10\\AD+FB=10-6=4\\AD+AD=4 ( \because ~FB=AD )\\2AD=4\\AD=4/2=2[/tex]