Question

What is the rotational inertia (moment of inertia) of a 12-kg uniform rod, 0.30 m long, rotating about an axis perpendicular to the rod and passing through the center of the rod

Answer 1

Answer:

$I=0.54\ kg-m^2$

Explanation:

Given that,

Mass of a uniform rod, m = 12 kg

Length of the rod, l = 0.3 m

The moment of inertia rotating about an axis perpendicular to the rod and passing through the center of the rod is given by :

$I=\dfrac{ml^2}{2}\\\\I=\dfrac{12\times (0.3)^2}{2}\\\\I=0.54\ kg-m^2$

So, the moment of inertia of the rod is $0.54\ kg-m^2$