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Answer:

E = 134.85 N/C

Explanation:

We are given;

Electric field location; b = <-0.2, -0.4, 0> m

Charge: q = 3 nc = 3 × 10^(-9) C

From the location given, we have total distance;

r = √((-0.2²) + (-0.4)² + (0²))

r = √0.2

Formula for Electric field is;

E = kq/r²

where;

k is a constant with a value of 8.99 x 10^(9) N.m²/C²

q is charge on the proton particle with a costant value = 1.6 × 10^(-19) C

r is the distance

Plugging in the relevant values, we have;

E = (8.99 x 10^(9) × 3 × 10^(-9))/(√0.2)²

E = 134.85 N/C

     The Answer is: E = 134.85 N/C

  • We are given;
  • Then Electric field location; b is = <-0.2, -0.4, 0> m
  • Then Charge: q = 3 nc = 3 × 10^(-9) C
  • After that From the location given, we have total distance;
  • Then r = √((-0.2²) + (-0.4)² + (0²))
  • Then r = √0.2

The Formula for Electric field is;

  • Then E = kq/r²
  • where;
  • After that k is a constant with a value of 8.99 x 10^(9) N.m²/C²
  • Then q is charge on the proton particle with a constant value is = 1.6 × 10^(-19) C
  • Then r is the distance
  • After that Plugging in the relevant values, we have;
  • Then E = (8.99 x 10^(9) × 3 × 10^(-9))/(√0.2)²
  • Thus, E = 134.85 N/C

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