Answer:
11577.25 Joules
Explanation:
The expression given in the question which is
[tex]k= \frac{1}{2} mv^2[/tex]
Is the expression for the kinetic energy stored in a system and it is measured in Joules
From the expression we can see that
mass m=210 kg
velocity v= 10.5 m/s
Substituting as seen in the question we have the kinetic energy as
[tex]k= \frac{1}{2}*210*10.5^2\\\\k= \frac{1}{2}*210*110.25\\\\k= \frac{1}{2} *23152.5\\\\k= 11577.25 J[/tex]
hence the energy stored is 11577.25 Joules
