Does anyone know this?

Answer:
[tex]\Huge \boxed{-2}[/tex]
Step-by-step explanation:
[tex]f(x)=-2x^2-2x+10[/tex]
For f(2), the input of the function is 2.
Let x = 2.
[tex]f(2)=-2(2)^2-2(2)+10[/tex]
Evaluate.
[tex]f(2)=-2(4)-2(2)+10[/tex]
[tex]f(2)=-8-4+10[/tex]
[tex]f(2)=-2[/tex]
Answer:
[tex]f(x) = - 2 {x}^{2} - 2x + 10[/tex]
put the value of x = 2
[tex]f(2) = - 2( {2}^{2} ) - 2(2) + 10[/tex]
[tex] f(2) = - 8 - 4 + 10[/tex]
[tex]f(2) = - 12 + 10[/tex]
[tex]f(2) = - 2[/tex]
hope it helps u