Answer:
Step-by-step explanation:
Ara of a triangle = 1/2 * base * height.
Before we find the area, we must look for all the sides of the triangle by taking the difference between any two points.
Given D = √(x₂-x₁)²+(y₂-y₁)²
Given the coordinates P(7,-3), Q(4,-3), R(4,9)
For the coordinates P(7,-3), Q(4,-3)
Given PQ = √(4-7)²+(-3+3)²
PQ = √(-3)²+0
PQ = √9
PQ = 3
For coordinates P(7,-3), R(4,9)
Given PR = √(4-7)²+(9+3)²
PR = √(-3)²+12²
PR = √9+144
PR = √153
For coordinates Q(4,-3), R(4,9)
Given QR = √(4-4)²+(9+3)²
QR = √(0)²+12²
QR = √0+144
QR = 12
Since it is a rright angled triangle, the base of the triamgle will be QR and the height will be PQ since the longest side is PR
Area of the triangle = 1/2 * PQ*QR
Area of the triangle = 1/2 * 12*6
Area of the triangle = 6*6
Area of the triangle = 36 square units