Which statement best explains why the sine of an acute angle is equal to the cosine of the angles complement
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Answer:
Option (B)
Step-by-step explanation:
From the figure attached,
ΔABC is a right triangle.
Cosine and Sine ratios from the given triangle will be,
SinA = [tex]\frac{\text{Opposite side}}{Hypotenuse}[/tex]
= [tex]\frac{a}{c}[/tex]
CosB = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{a}{c}[/tex]
Therefore, both the ratios (Sine and Cosine) will be equal as [tex]\frac{a}{c}[/tex]
Option (B) will be the correct option.