Question

evaluate the expression

Answer 1

Answer:

$12-[20-2(6^2\div3\times2^2)]=88$

Step-by-step explanation:

So we have the expression:

$12-[20-2(6^2\div3\times2^2)]$

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

$12-[20-2(6^2\div3\times2^2)]$

The parentheses is:

$(6^2\div3\times2^2)$

Square the 6 and the 4:

$(36\div3\times4)$

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

$(36\div3\times4)\\=(12\times4)\\=48$

Therefore, the original equation is now:

$12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]$

Multiply with the brackets:

$=12-[20-96]$

Subtract with the brackets:

$=12-[-76]$

Two negatives make a positive. Add:

$=12+76=88$

Therefore:

$12-[20-2(6^2\div3\times2^2)]=88$