Question

A projectile is fired vertically upward from a height of 300
300
feet above the ground, with an initial velocity of 900
900
ft/sec. Recall that projectiles are modeled by the function h(t)=−16t2+v0t+y0
h
(
t
)
=
−
16
t
2
+
v
0
t
+
y
0
. Write a quadratic equation to model the projectile's height h(t)
h
(
t
)
in feet above the ground after t seconds.

Answer 1

Step-by-step explanation:

It is given that, a projectile is fired vertically upward from a height of 300  feet above the ground, with an initial velocity of 900 ft/s.

The general equation with which a projectile are modled by the function is given by :

$h(t)=-16t^2+v_ot+y_o$

y₀ is the initial height above the ground

v₀ = initial velocity

So,

$h(t)=-16t^2+900t+300$

This is the quadratic equation that models the projectile height in feet above the ground after t seconds.