Moving mirror M2 of a Michelson interferometer a distance of 90 μm causes 470 bright-dark-bright fringe shifts.What is the wavelength of the light?

Respuesta :

Answer:

Wavelength, [tex]\lambda=382.9\ nm[/tex]

Explanation:

It is given that,

Distance moved by mirror in Michelson interferometer is 90 μm

Number of bright fringe shift = 470

We need to find the wavelength of the light.

For Michelson interferometer experiment,

[tex]2d=m\lambda[/tex]

here, [tex]\lambda[/tex] is the wavelength of the light

[tex]\lambda=\dfrac{2d}{m}\\\\\lambda=\dfrac{2\times 90\times 10^{-6}}{470}\\\\\lambda=3.829\times 10^{-7}\ m\\\\\lambda=382.9\ nm[/tex]

So, the wavelength of the light is 382.9 nm.

The wavelength of the light should be 382.9nm.

Calculation of the wavelength of the light:

Since

Distance moved by the mirror in Michelson interferometer is 90 μm

And, Number of bright fringe shift = 470

So

we know that

2d = m*wavelength

wavelength = 2*90*10^-6/470

= 3.829*10^-7m

= 382.9nm

hence, The wavelength of the light should be 382.9nm.

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