Question

Using the Bohr model, find the ionization energy of the ground He ion.

Answer 1

Answer:

54.4ev

Explanation:

Using

E = - me⁴Z²/8Eo²h²n²

Where n= 1

Z= 1

h=6.6E-31Js

me= 9.1x 10-31kg

Eo=8.85E-12m-3 kg-1 s4 A2

So by substituting

E= -(9.1x 10-31kg)⁴x 1²/8(8.85E-12m-3 kg-1 s4 A2)² x (6.6E-31Js)² x 1²

So E= 54.4ev