Answer:
Chlorine
Explanation:
Hello.
In this case, for the given elements, we are able to know that oxygen has 6 valence electrons, chlorine 7, nitrogen 5 and neon 8, therefore neon is not able to react as it already has 8 valence electrons. Besides, the element having the most valence electrons is chlorine and its reaction with hydrogen forms hydrogen chloride as shown below:
[tex]H_2(g)+Cl_2(g)\rightarrow 2HCl(g)[/tex]
Therefore, the required element is chlorine.
Regards.
Chlorine element would have the most valence electrons and also be able to react with hydrogen
The atomic number of hydrogen is 1 and its electronic configuration is [tex]1s^{1}[/tex] .
The atomic number of oxygen is 8 and its electronic configuration is [tex]1s^{2} 2s^{2} 2p^{4}[/tex]. The valence electron in oxgen is 6.
The atomic number of chlorine is 17 and its electronic configuration is [tex]1s^{2} 2s^{2} 2p^{6}3s^{2} 3p^{5}[/tex]. The valence electron in chlorine is 7.
The atomic number of neon is 10 and its electronic configuration is [tex]1s^{2} 2s^{2} 2p^{6}[/tex]. The valence electron in neon is 8.
The atomic number of nitrogen is 7 and its electronic configuration is [tex]1s^{2} 2s^{2} 2p^{3}[/tex]. The valence electron in nitrogen is 5.
Except Neon, all three atoms will react with hydrogen as the configuration of neon is a stable electronic configuration.
Chlorine has the greatest number of valence electrons after neon that is 7. So, chlorine would have the most valence electrons and also be able to react with hydrogen as follows:-
[tex]H_2+Cl_2\rightarrow2HCl[/tex]
Hence, the correct answer is chlorine.
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