Respuesta :
Answer:
[tex]\triangle ABC \cong \triangle EDF[/tex]
by SSS congruence.
Step-by-step explanation:
Given the two triangles with following coordinates and angles:
[tex]\underline{\triangle ABC:}[/tex]
A(0, 0)
B(2, 4)
C(0, 2)
[tex]\angle C = 135^\circ\\\angle B = 30^\circ[/tex]
[tex]\underline{\triangle D EF :}[/tex]
D(2, 0)
E(4, 4)
F(4, 2)
[tex]\angle F = 135^\circ\\\angle D = 30^\circ[/tex]
Let us calculate the sides of the two triangles one by one.
Distance formula:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex](x_1, x_2)[/tex] and [tex](y_1, y_2)[/tex] are the two coordinates of which distance is to be calculated.
[tex]AB = \sqrt{(4-0)^2+(2-0)^2} = \sqrt{20}[/tex]
[tex]BC = \sqrt{(0-2)^2+(2-4)^2} = \sqrt{8}[/tex]
[tex]AC= \sqrt{(0-0)^2+(0-2)^2} = 2[/tex]
[tex]DE = \sqrt{(4-2)^2+(4-0)^2} = \sqrt{20}[/tex]
[tex]EF = \sqrt{(4-4)^2+(4-2)^2} = 2[/tex]
[tex]DF= \sqrt{(4-2)^2+(2-0)^2} = \sqrt8[/tex]
Sides AB = DE
BC = DF and
AC = EF
All the three sides are equal here. So SSS (Side Side Side) congruence.
And angles:
[tex]\angle C = \angle F =135^\circ\\\angle B =\angle D = 30^\circ[/tex]
Therefore,
[tex]\triangle ABC \cong \triangle EDF[/tex] by SSS congruence.
Answer:
by SSS congruence.
Step-by-step explanation:
Given the two triangles with following coordinates and angles:
A(0, 0)
B(2, 4)
C(0, 2)
D(2, 0)
E(4, 4)
F(4, 2)
Let us calculate the sides of the two triangles one by one.
Distance formula:
and are the two coordinates of which distance is to be calculated.
Sides AB = DE
BC = DF and
AC = EF
All the three sides are equal here. So SSS (Side Side Side) congruence.
And angles:
Therefore,
by SSS congruence.
Step-by-step explanation: