Question

How fast must a meter stick be moving if its length is observed to shrink to 0.57 m?

Answer 1

Answer:

0.8216c

Explanation:

Using the relationship

L' = L√(1 - v²/c²)

where

L = original length,

L' = observed length,

v = velocity,

c =speed.

L'/L = 0.57

Then

0.57 = √(1 - v²/c²)

1 - v²/c² = 0.57² = 0.3249

v²/c² = 1 - 0.3249 = 0.6751

v² = 0.6751c²

v = c√0.6751 = 0.8216c

Explanation: