Question

Fill in the nuclide symbol for the missing particle in the following nuclear equation.

_______ → + 0 e1 + 13C6

Answer 1

Answer:

Nitrogen 13

Explanation:

We need fill in the blank the nuclide symbol for the missing particle in the following nuclear equation.

$X\rightarrow ^0e_1+^{13}C_6$

In this reaction, the emission of positron takes place. The atomic number in the LHS and the RHS should be same. So,

$^{13}_7 N \rightarrow ^0e_1+^{13}C_6$

So, the LHS have nitrogen 13, a radioactive isotope.