Question

An object on the end of a spring is oscillating in simple harmonic motion. If the amplitude of oscillation is doubled, how does this affect the object’s maximum speed?

Answer 1

Answer:

The maximum speed of the oscillating object doubles as well.

Explanation:

The oscillatory motion of the object on the spring can be modelled using this equation below:

$Vmax= A\omega$

Where

Vmax = the maximum speed of the oscillating object.

A = Amplitude of the oscillating object.

$\omega$ = angular velocity of the oscillating object.

If the amplitude, A becomes doubled, the new amplitude will be = 2A.

As a result,  $Vmax = 2 A \omega$

This shows that the maximum speed has doubled in its value