determine whether the sum of two values is a rational number or an irrational number.
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Answer:
1). Rational
2). Irrational
3). Rational
4). Rational
5). Irrational
Step-by-step explanation:
To solve this question we should follow the rule,
"Addition of rational and an irrational number is an irrational number."
1). [tex]\sqrt{16}=4[/tex] (rational number)
[tex]-\frac{21}{5}[/tex] (negative rational number)
[tex]\sqrt{16}-\frac{21}{5}=4-\frac{21}{5}[/tex]
[tex]=-\frac{1}{5}[/tex] [rational number]
2). π → (Irrational number)
24 → (rational number)
π + 24 → (Irrational number)
Since addition of a rational and an irrational number is an irrational number.
3). [tex]\sqrt{4}[/tex] = 2 (rational number)
5 (rational number)
2 + 5 = 7 (rational number)
4). [tex]\sqrt{36}=6[/tex] (rational number)
[tex]\sqrt[3]{27}=3[/tex] (rational number)
[tex]\sqrt{36}+\sqrt[3]{27}=9[/tex] (rational number)
5). [tex]\frac{3}{4}[/tex] (rational number)
[tex]\sqrt{27}[/tex] → (Irrational number)
[tex]\frac{3}{4}+\sqrt{27}[/tex] → (Irrational number)