Answer:
0.0228
Step-by-step explanation:
Given that:
mean (μ) = 75, Standard deviation (σ) = 3.5
The z score is a score used in statistics to measure by how many standard deviations the raw score is above or below the mean. If the z score is positive, it means that the raw sore is above the mean and if the z score is negative then the raw score is below the mean. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma}\\ \\For\ a\ sample \ n, the\ z\ score\ is:\\ \\z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]
For x > 76 and a sample (n) = 49:
[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n} } }\\\\z=\frac{76-75}{\frac{3.5}{\sqrt{49} } }=2[/tex]
From the normal distribution table, the probability that the average score of the 49 players exceeded 76 = P(x > 76) = P(z > 2) = 1 - P(z < 2) = 1 - 0.9772 = 0.0228
