Question

The magnetic flux through a certain coil is given by φm = (1/50π) cos 100πt
where the units are SI. The coil has 100 turns. The magnitude of the induced EMF when t = 1/200 s is:_______.
A. 1/50π V
B. 2/π V
C. 100 V
D. zero
E. 200 V

Answer 1

Answer:

A. 1/50π V

Explanation:

Given;

magnetic flux through the coil, φm = (1/50π) cos 100πt

t = 1/200 s

The magnitude of the induced EMF is given by;

$EMF = \frac{d \phi_m}{dt} \\\\EMF =\frac{d}{dt} (1/50 \pi)cos \ 100\pi t)\\\\EMF = (1/50 \pi)cos \ 100\pi \\\\EMF =(1/50 \pi)cos \ 100 *180\\\\ EMF =(1/50 \pi)cos \ 18000\\\\ EMF =(1/50 \pi) (1)\\\\EMF =(1/50 \pi) \ V$

Therefore, the magnitude of the induced EMF is 1/50π V

The correct option is "A. 1/50π V"