Answer:
Step-by-step explanation:
y = 6x + 2
Slope = 6
A line perpendicular to this would have a negative reciprocal slope = [tex]-\frac{1}{6}[/tex]
To solve for the y-intercept, plug the coordinates given into the question.
y = mx + b
5 =[tex]-\frac{1}{6}[/tex] (3) + b
5 = [tex]-\frac{3}{6}[/tex] + b
5 = [tex]-\frac{1}{2}[/tex] + b
b = 5 + [tex]\frac{1}{2}[/tex]
b = [tex]\frac{11}{2}[/tex] or 5 [tex]\frac{1}{2}[/tex]
So, your new slope-intercept line equation is
y = [tex]-\frac{1}{6}[/tex]x + 5 [tex]\frac{1}{2}[/tex]
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