A person is lying on a diving board 3.00 m above the surface of the water in a swimming pool. She looks at a penny that is on the bottom of the pool directly below her. To her, the penny appears to be a distance of 8.00 m from her.

Required:
What is the depth of the water at this point?

Respuesta :

Answer:

The  depth of water at the point is  [tex]d_A = 6.55 \ m[/tex]

Explanation:

From the question we are told that

   The height of the person above water   is  [tex]d = 3.00 \ m[/tex]

   The distance  of the coin as seen by the person  is [tex]d' = 8.00 \ m[/tex]

Generally the apparent depth is mathematically represented as

      [tex]d_a = \frac{d_A}{n}[/tex]

Here [tex]d_A[/tex] is the actual depth of water while  n is the refractive index of water with a constant value [tex]n = 1.33[/tex]

Now from the point the person is the apparent depth is evaluated as

     [tex]d_a = d'-d[/tex]

=>   [tex]d_a = 8 - 3[/tex]

=>  [tex]d_a = 5 \ m[/tex]

So

     [tex]5 = \frac{d_A}{1.33}[/tex]

=>   [tex]d_A = 5 * 1.33[/tex]

=>   [tex]d_A = 6.55 \ m[/tex]

     

   

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