Answer:
1. confidence interval = (0.163, 7.237)
1. confidence interval = (0.163, 7.237)2. t = 2.366
1. confidence interval = (0.163, 7.237)2. t = 2.3663. critical value of one tailed test = 1.833
Step-by-step explanation:
before after dt(before - after) d²
74 73 1 1
83 77 6 36
75 70 5 25
88 77 11 121
84 74 10 100
63 67 -4 16
93 95 -2 4
84 83 1 1
91 84 7 49
77 75 2 4
∑dt = 37
d* = 37/10
since sample space = 10
d* = 3.7
s.d from the question = 4.95
df = 10 - 1 = 9
critical value at 0.05 significance
t(0.025 at df of 9) = ±2.262
marginal error computation:
= (2.262) × (4.945/√10)
= 2.262 × 1.5637
= 3.5370
confidence interval CI = d* + marginal error
= 3.7 ±3.5730
= (0.163, 7.237)
The logic course give an improvement on abstract reasoning. The confidence interval shows that the result is significant.
H₀: Цd = 0
H₁: Цd > 0
∝ = 0.05
t = (3.7 - 0)/(4.945/√10)
t = 3.7/1.564
t = 2.366
for a right tailed test at 0.05 significance, and df of 9, the critical value is 1.833
please refer to the attachment to see the rejection region.
