Answer:
Step-by-step explanation:
[tex](x-h) ^2+(y-k) ^2 =r^2[/tex]
The above equation is the general standard equation for the circle centered at (h,k) with radius r
Given that the equation of the circle is
[tex](x-2) ^2+(y+3) ^2 =25[/tex]
Comparing this with the general equation we can get the center and the radius as
[tex](x-h) ^2+(y-k) ^2 =r^2\\(x-(2)) ^2+(y-(-3)) ^2 =5^2[/tex]
We can now see that
h= 2
k= -3 and
r= 5