Answer:
Well, in the local reservoir we have an initial amount of water A.
And per hour, the amount of water in the reservoir decreases by 500 gals.
So after t hours, the amount of water in the reservoir is:
W = A - 500gal*t
This is a linear equation, so the model that fits best in the given situation is a linear model.
Where the only thing that you need to take in mind, is that the domain of this model is restricted:
This is because we can not have a negative amount of water in the reservoir, so the maximum value of t accepted is:
W = 0 = A - 500gal*t
t = A/500 hours
So the domain of this linear relation is:
t ∈ {0h, A/500 }
