Question

Events A and B are mutually exclusive. Find the missing probability.


P(A) = 1/4 P(B) = 13/20 P(A or B) = ?


4/5


1/2


9/10


3/8

Answer 1

Answer:

Option C.

Step-by-step explanation:

It is given that,

$P(A)=\dfrac{1}{4}$

$P(B)=\dfrac{13}{20}$

It is given that events A and B are mutually exclusive. It means they have no common elements.

$P(A\cap B)=0$

We know that,

$P(A\ or\ B)=P(A\cup B)=P(A)+P(B)-P(A\cap B)$

On substituting the values, we get

$P(A\cup B)=\dfrac{1}{4}+\dfrac{13}{20}-0$

$P(A\cup B)=\dfrac{5+13}{20}$

$P(A\cup B)=\dfrac{18}{20}$

$P(A\cup B)=\dfrac{9}{10}$

Therefore, the correct option is C.

Answer 2

The P (A or B) should be $\frac{9}{10}$

Given that,

• P(A) = 1 by 4  P(B) = 13 by 20

Based on the above information, the calculation is as follows:

$= \frac{1}{4} + \frac{13}{20}\\\\= \frac{5+13}{20} \\\\= \frac{18}{20}\\\\= \frac{9}{10}$

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