Question

Draw the image of ABC under dilation whose center is P and scale factor is 4.

Answer 1

Answer:

Step-by-step explanation:

Let the point P is origin (0, 0), segment AB lies on the x-axis and segment PC on the y-axis,

Coordinates of A, B and C will be (1, 0), (2, 0) and (0, 2).

When triangle ABC is dilated by a scale factor 4 about the origin,

Rule for dilation;

(x, y) → (4x, 4y)

New coordinates of the points A, B and C will be,

A(1, 0) → A'(4, 0)

B(-2, 0) → B'(-8, 0)

C(0, 2) → C'(0, 8)

By plotting points A', B' and C' we can get the dilated image A'B'C'.

Answer 2

Dilation involves changing the size of a shape.

Assume point P is the center of origin, then we have the following coordinates of ABC

$A = (1,0)$

$B = (-2,0)$

$C = (0,2)$

The scale factor (k) is given as:

$k= 4$

So, the dilation rule is represented as:

$(x,y) \to (4 \times (x,y)$

Using the above dilation rule, the following coordinates represent the image of triangle ABC

$A' = (4,0)$

$B' = (-8,0)$

$C = (0,8)$

See attachment for the image of the dilation.

Read more about dilation at:

https://brainly.com/question/8532602