Answer:
(a) The mean of the weight of the mice is 50.26 grams.
(b) The standard deviation of the weight of the mice is 14.08 grams.
Step-by-step explanation:
(a)
The mean is given as follows:
[tex]\bar X=\frac{\sum f_{i}x_{i}}{\sum f_{i}}[/tex]
[tex]=\frac{5026}{100}\\\\=50.26[/tex]
Thus, the mean of the weight of the mice is 50.26 grams.
(b)
Compute the standard deviation as follows:
[tex]s=\frac{1}{\sum f_{i}-1}[\sum f_{i}x_{i}^{2}-\frac{1}{\sum f_{i}}(\sum f_{i}x_{i})^{2}][/tex]
[tex]=\frac{1}{100-1}[254001-\frac{1}{100}(5026)^{2}]\\\\=\frac{1}{99}\times 1394.24\\\\=14.08323\\\\\approx 14.08[/tex]
Thus, the standard deviation of the weight of the mice is 14.08 grams.