Question

Determine the number of solutions for each quadratic.

1.) 4x^2-3x+4=0

2.)9x^2-12x+4=0


PLEASE HELP!!!

Answer 1

Answer:

1. no solution 2. has one solution

Step-by-step explanation:

first you must find the discriminant of each quadratic also remember

if the discriminant is positive  b^{2}-4ac> 0, then the quadratic equation has two solutions.

if the discriminant is equal  b^{2}-4ac= 0, then the quadratic equation has one solution.

if the discriminant is negative  b^{2}-4ac< 0, then the quadratic equation has no solution.

1. the discriminant is $\sqrt{b^2-4ac}$ and when you plug in the numbers you get -55 which is less than 0

2. the discriminant is 0 so there is one solution

Answer 2

Answer:

1. has no real roots, no solutions (unless you can have imaginary solutions)

2. touches the x axis in one point, so one solution

Step-by-step explanation: