Answer:
72mile/hr
Step-by-step explanation:
Let d be distance in mile
Let r be average rate in mile/hr
Let t be time in hr
d = r × t
t = d/r
360/r = t ........1
Also
The question stated that the average speed was 6 less to travel a distance of 330mile at the same time.
Since the average speed is r, hence 6 less that r = r-6 at the same time
Therefore
330/r-6 = same time ( t ) .......2
Equate 1 and 2
360/r = 330/r-6
Cross multiply
360(r-6) = 330(r)
360r - 360×6 = 330r
360r - 2160 = 330r
Collecting like terms
- 2160 = 330r - 360r
- 2160 = - 30r
Divide both sides by - 30
- 2160/ - 30 = - 30r/ - 30
r = 72mile/hr
Hence the average speed is 72mile/hr