Answer:
Step-by-step explanation:
Given question is incomplete; here is the complete question.
∆ PQR shown in the figure below is transformed into ∆ STU by a dilation with center (0, 0) and a scale factor of 3.
Complete the following tasks,
- Draw ΔSTU on the same set of axes.
- Fill in the coordinates of the vertices of ΔSTU.
- Complete the statement that compares the two triangles.
When ΔPQR is transformed into ΔSTU by a dilation with center (0, 0) and a scale factor of 3,
Rule to followed to get the vertices of ΔSTU,
(x, y) → (3x, 3y)
P(1, 1) → S(3, 3)
Q(3, 2) → T(9, 6)
R(3, 1) → U(9, 3)
Length of QR = 2 - 1 = 1 unit
Length of PQ = [tex]\sqrt{(3-1)^2+(2-1)^2}=\sqrt{5}[/tex] units
Length of PR = 3 - 1 = 2 units
Length of ST = [tex]\sqrt{(9-3)^2+(6-3)^2}=3\sqrt{5}[/tex] units
Length of TU = 6 - 3 = 3 units
Length of SU = 9 - 3 = 6 units
Therefore, ratio of the corresponding sides of ΔPQR and ΔSTU,
[tex]\frac{\text{PQ}}{\text{ST}}=\frac{\text{QR}}{\text{TU}}=\frac{\text{PR}}{\text{SU}}[/tex]
[tex]\frac{\sqrt{5}}{3\sqrt{5}}=\frac{1}{3}=\frac{2}{6}[/tex]
[tex]\frac{1}{3}=\frac{1}{3}=\frac{1}{3}[/tex]
Since ratio of the corresponding sides are same,
Therefore, ΔPQR and ΔSTU are similar.
